3x^2+405x-534600=0

Solution for 3x^2+405x-534600=0 equation:

3x^2+405x-534600=0

a = 3; b = 405; c = -534600;
Δ = b2-4ac
Δ = 4052-4·3·(-534600)
Δ = 6579225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6579225}=2565$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(405)-2565}{2*3}=\frac{-2970}{6}
=-495
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(405)+2565}{2*3}=\frac{2160}{6}
=360
$